x^2+180x-300=0

Solution for x^2+180x-300=0 equation:

x^2+180x-300=0

a = 1; b = 180; c = -300;
Δ = b2-4ac
Δ = 1802-4·1·(-300)
Δ = 33600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{33600}=\sqrt{1600*21}=\sqrt{1600}*\sqrt{21}=40\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-40\sqrt{21}}{2*1}=\frac{-180-40\sqrt{21}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+40\sqrt{21}}{2*1}=\frac{-180+40\sqrt{21}}{2}
$